wonderwords
Generate random english words and phrases.
Decision gist · record as of 2026-08-14
Yes. The package is stable, dependency-free, well-documented, and solves a straightforward problem with a clean API. The aging maintenance status (288 days since last release) is not a blocker for a mature utility package with no known vulnerabilities. Install it if you need random word or sentence generation; the low friction and permissive license make it a safe choice.AI-flagged interpretation of the facts on this page — verify before relying
Before you install
- Low friction install with no runtime dependencies.
- Maintenance status is aging—last release was 288 days ago—but the repository remains active and the package is marked Production/Stable.
License · maintenance · safety
permissive license (permissive) — MIT License permits unrestricted use, modification, and distribution with only attribution and liability disclaimer required. No restrictions on commercial or private use.
last release 2025-10-30 (288 days) · last repo commit 2025-10-30 · 72 stars
0 known vulnerabilities (OSV.dev, 2026-08-14) · 632,486 downloads/mo, #5,650 on PyPI
Alternatives
Verify before relying
pip install wonderwords
from wonderwords import RandomWord
r = RandomWord()
print(r.word())
print(r.word(starts_with="a", word_max_length=8))
print(r.random_words(3, include_parts_of_speech=["nouns"]))- Whether the word list is comprehensive enough for production use cases requiring specialized vocabulary domains.
- Performance characteristics when filtering against very large result sets or complex regex patterns.
- Whether custom word lists can be loaded from external sources or must be defined in code.
What it is and what it does
Wonderwords is a pure-Python library for generating random English words and sentences. It provides a RandomWord class for generating individual words with optional filters (length, starting/ending patterns, part of speech, regex matching) and a RandomSentence class for generating structured random sentences. The package includes a command-line interface for quick generation without writing code.
The library has no external runtime dependencies and supports Python 3.8 through 3.12. It's useful for test data generation, placeholder text, creative writing tools, or any application needing randomized English vocabulary. The API is straightforward—instantiate a class and call methods with optional filter parameters—and the documentation is comprehensive.
Use it for
- Generate test data and fixtures for unit tests without hardcoding specific word values.
- Create placeholder or dummy text in applications during development or prototyping.
- Build word games, puzzles, or educational tools that need randomized vocabulary.
- Populate database seeds or sample datasets with realistic English words.
- Generate random prompts or creative writing seeds for brainstorming tools.
Worth the install?
AI-flagged interpretation of the facts on this page. Verify before relying on it.
Yes.
The package is stable, dependency-free, well-documented, and solves a straightforward problem with a clean API. The aging maintenance status (288 days since last release) is not a blocker for a mature utility package with no known vulnerabilities. Install it if you need random word or sentence generation; the low friction and permissive license make it a safe choice.
Install
wonderwords on PyPI
Before you install
Low friction install with no runtime dependencies. Maintenance status is aging—last release was 288 days ago—but the repository remains active and the package is marked Production/Stable.
License in practice
MIT License permits unrestricted use, modification, and distribution with only attribution and liability disclaimer required. No restrictions on commercial or private use.
Quickstart
pip install wonderwords
from wonderwords import RandomWord
r = RandomWord()
print(r.word())
print(r.word(starts_with="a", word_max_length=8))
print(r.random_words(3, include_parts_of_speech=["nouns"]))Verify before relying
- Whether the word list is comprehensive enough for production use cases requiring specialized vocabulary domains.
- Performance characteristics when filtering against very large result sets or complex regex patterns.
- Whether custom word lists can be loaded from external sources or must be defined in code.
Package facts
| License | permissive license permissive |
| Python support | Supports the current Python release >=3.8 |
| Install friction | Low. Pure-Python wheel |
| Runtime dependencies | None |
| Maintenance | Aging 288 days since the last release |
| Last repo commit | |
| First released | |
| Downloads | 632,486 / month, #5,650 on PyPI 30-day window, as of 2026-08-14 |
| Known vulnerabilities | None known OSV.dev, checked 2026-08-14 |
| Classifiers | Development Status :: 5 - Production/StableLicense :: OSI Approved :: MIT LicenseNatural Language :: EnglishOperating System :: OS IndependentProgramming Language :: Python :: 3Programming Language :: Python :: 3.10Programming Language :: Python :: 3.11Programming Language :: Python :: 3.12Programming Language :: Python :: 3.8Programming Language :: Python :: 3.9Topic :: Text Processing :: Linguistic |
Evidence: wonderwords-3.0.1-py3-none-any.whl
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